Kitabmanaqibnurulburhanpdfdownload [PATCHED]

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Just a guess based on the non-common variable names : the output of your application is full of stuff that is either not needed or that is needed at some other point in your program.
Most likely, a garbage variable is causing your error. is worth $ 1,804,880.00

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How to get a variable’s name as a string in C++, to compare it with a string value?

I have an integer variable, lets say it is named userID. I want to compare it’s value with a string. I tried “userID”, but that didn’t work. How can I compare it with a string variable? I have these variable in a class named Player.


Even though you are not pasting the code, I’m assuming your code compiles and run is as follows:
std::string a = “userID”;

So, either of the following would work:
const std::string s = “userID”;

auto ref = [&] {
return a;

auto ref1 = [&] {
return *s;

auto ref2 = [&] {
return *reinterpret_cast(&a);

That last one seems very unsafe, since you are accessing a variable that is not yours by passing a pointer to it. For example, this is called slicing and it can be avoided by the first two.
However, it should be clear that the same thing can be done with the as operator:
auto a_as_str = a;

This is the same as ref1. However, if you were to change the class member in the above example to a reference:
void Player::setUserID(std::string &userID


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