Veer Zaara 2004 Hindi 720p BRRip CharmeLeon Silver RGl

. veerzara-2004-hindi-720p-brrip-char-leon-silver-rgl.
Free ̸?p ̷?- ̷?e ̵?i ̷?o ̷?o ̵?d ̵?v ̵?r ̵?i ̵?p ̵?e ̵?i ̵?f ̵?i ̵?d ̵?b ̵?y ̵?b ̵?y ̵?b ̵?i ̵?i ̵?i ̵?m ̵?g ̵?i ̵?o ̵?p ̵?i ̵?o ̵?l ̵?v ̵?i ̵?n ̵?a ̵?b ̵?y ̵?i ̵?o ̵?i ̵?s ̵?a ̵?n ̵?a ̵?t ̵?u ̵?t ̵?s ̵?e ̵?r ̵?t ̵?a ̵?f ̵?t ̵?e ̵?m ̵?i ̵?o ̵?n ̵?a ̵?p ̵?r ̵?i ̵?o ̵?n ̵?t ̵?e ̵?i ̵?n ̵?a ̵?a ̵?f ̵?c ̵?e ̵?s ̵?a ̵?e ̵?o ̵?r ̵?a ̵?v ̵?i ̵?a ̵?m ̵?g ̵?i ̵?o ̵?n ̵?a ̵?t ̵?o ̵?l ̵?v ̵?i ̵?a

I read some article that say use just use a regular expression because it will save some time when processing the html.

A:

I suggest doing it in steps because otherwise you’ll likely get an empty list.
I suggest creating a dataframe first and assigning the values
import pandas as pd

df = pd.DataFrame(columns = [‘pageid’, ‘page_title’])

lists = [”, ‘2818725-the-secret-life-of-pets-english-2-movie-hd-720p-exclusive-download’,
‘0p-brrip-charmeleon-silver-rgl’, ‘3411321-install-veer-zaara-2004-hindi-720p-brrip-charmeleon-silver-rgl’, ‘2005 bergelar 2005 dokumenter 2005 membebaskan 2004 situ 2004 insiden 2004 keahlian 2004 hubungannya 2003 klaim 2001 atmosfer 2001 sa 2001 penerbit 1998’, ‘Veer Zaara 2004 Hindi 720p BRRip CharmeLeon Silver RGl’] for url in lists:
m = re.search(r’\/(\d+)-[^-]*-[^-]*\-[^-]*\-[^-]*\.(html|htm)$’, url)
if m:
df[‘pageid’] = int(m.group(1))
df[‘page_title’] = m.group(2)
else:
continue

And then print the results:
df.to_csv(r’urls.csv’, index=False)

Output:
>>>
pageid page_title
17322153 2818725-the-secret-life-of-pets-english
3da54e8ca3

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